A high-voltage powerline operates at 500 000 V-rms and carries an rms current of 500 A.If the resistance of the cable is 0.050 $\Omega$ /km, what is the resistive power loss in 200 km of the powerline?
A)250 kW
B)500 kW
C)1 Megawatt
D)2.5 Megawatts
E)250 Megawatts

Question

Quizplus · Accepted Answer

The resistive power loss can be calculated using the formula:

Power loss = Resistance x Current^2 x Length

Length is given as 200 km or 200,000 m. The resistance is given as 0.050 ohm/km or 0.050 ohm/1000 m.

Substituting the given values, we get:

Power loss = 0.050 x (500)^2 x 200,000
           = 2,500,000 Watts or 2.5 Megawatts

Therefore, the best choice is D) 2.5 Megawatts.

A High-Voltage Powerline Operates at 500 000 V-Rms and Carries Ω\OmegaΩ

A High-Voltage Powerline Operates at 500 000 V-Rms and Carries $\Omega$