If an R = 1.0-k $\Omega$ resistor, a C = 1.0-$\mu$F capacitor, and an L = 0.20-H inductor are connected in series with a V = 150 sin (377t) volts source, what is the maximum current delivered by the source?
A)0.007 0 A
B)27 mA
C)54 mA
D)0.31 A
E)0.34 A

Question

Quizplus · Accepted Answer

The maximum current in an RLC series circuit is determined by the impedance Z, which is calculated using Z = √(R² + (XL - XC)²), where XL = ωL and XC = 1/(ωC). Here, ω = 377 rad/s. Calculate XL = 377 * 0.20 = 75.4 Ω and XC = 1/(377 * 1.0e-6) = 2652.9 Ω. Then, Z = √(1.0² + (75.4 - 2652.9)²) ≈ 2577.5 Ω. The maximum current Imax = Vmax/Z = 150/2577.5 ≈ 0.054 A or 54 mA.

If an R = 1 Ω\OmegaΩ Resistor, a C = 1 μ\muμ

If an R = 1 $\Omega$ Resistor, a C = 1 $\mu$