A 10-$\mu$F capacitor in an LC circuit made entirely of superconducting materials (R = 0 $\Omega$ ) is charged to 100 $\mu$C.Then a superconducting switch is closed.At t = 0 s, plate 1 is positively charged and plate 2 is negatively charged.At a later time, Vab = +10 V.At that time, Vdc is:
A)0 V.
B)3.54 V.
C)5.0 V.
D)7.07 V.
E)10 V.

Question

A 10-$\mu$F capacitor in an LC circuit made entirely of superconducting materials (R = 0  $\Omega$  ) is charged to 100 $\mu$C.Then a superconducting switch is closed.At t = 0 s, plate 1 is positively charged and plate 2 is negatively charged.At a later time, Vab = +10 V.At that time, Vdc is: 
A)0 V. 
B)3.54 V. 
C)5.0 V. 
D)7.07 V. 
E)10 V.

Quizplus · Accepted Answer

The Answer of A 10-$\mu$F capacitor in an LC circuit made entirely of superconducting materials (R = 0  $\Omega$  ) is charged to 100 $\mu$C.Then a superconducting switch is closed.At t = 0 s, plate 1 is positively charged and plate 2 is negatively charged.At a later time, Vab = +10 V.At that time, Vdc is: 
A)0 V. 
B)3.54 V. 
C)5.0 V. 
D)7.07 V. 
E)10 V.

A 10- μ\muμ F Capacitor in an LC Circuit Made Entirely of Superconducting

A 10- $\mu$ F Capacitor in an LC Circuit Made Entirely of Superconducting