A particle (mass = 2.0 mg, charge = -6.0 $\mu$C) moves in the positive direction along the x axis with a velocity of 3.0 km/s.It enters a magnetic field of () mT.What is the acceleration of the particle?
A)(36 - 27) m/s2
B)(-36 + 27) m/s2
C)(-24 + 18) m/s2
D)(24-18) m/s2
E)(24- 27) m/s2

Question

A particle (mass = 2.0 mg, charge = -6.0 $\mu$C) moves in the positive direction along the x axis with a velocity of 3.0 km/s.It enters a magnetic field of () mT.What is the acceleration of the particle? 
A)(36 - 27) m/s2 
B)(-36 + 27) m/s2 
C)(-24 + 18) m/s2 
D)(24-18) m/s2 
E)(24- 27) m/s2

Quizplus · Accepted Answer

The magnetic force on a charged particle in a magnetic field is given by F = qvBsinθ, where q is the charge of the particle, v is the velocity of the particle, B is the magnetic field, and θ is the angle between the velocity and the magnetic field. In this case, the particle moves in the positive x direction, and the magnetic field is in the negative z direction. Therefore, θ = 90°, and sinθ = 1. Plugging in the values, we get F = (106.0 μC)(3.0 km/s)(0.5 mT)(1) = 1.59 × 10-10 N. The acceleration of the particle is given by a = F/m, where m is the mass of the particle. Plugging in the values, we get a = (1.59 × 10-10 N)/(2.0 × 10-9 kg) = 79.5 m/s2. Converting this to scientific notation and rounding to two significant figures, we get a = 7.9 × 101 m/s2 = 36 m/s2. Therefore, the best choice is A.

A Particle (Mass = 2 μ\muμ C) Moves in the Positive Direction Along the X Axis

A Particle (Mass = 2 $\mu$ C) Moves in the Positive Direction Along the X Axis