Suppose a box contains about 5.0* 1021 hydrogen atoms at room temperature (21$\degree$C). Determine the thermal energy of these atoms.

Question

Quizplus · Accepted Answer

We can use the formula for thermal energy:
E = (3/2) RT
where R is the gas constant and T is the temperature in Kelvin. Assuming standard pressure and using the molar mass of hydrogen (1.008 g/mol), we can calculate the number of moles of hydrogen:
n = (5.0 x 10^21 atoms) / (6.022 x 10^23 atoms/mol) = 8.31 x 10^-3 mol
Converting the temperature to Kelvin:
T = (21°C + 273.15) K = 294.15 K
Using the formula:
E = (3/2) R T n
E = (3/2) (8.314 J/mol·K) (294.15 K) (8.31 x 10^-3 mol) = 30.0 J
Therefore, the thermal energy of these atoms is approximately 30 J.

Suppose a Box Contains About 5 °\degree° C) Determine the Thermal Energy of These Atoms

Suppose a Box Contains About 5 $\degree$ C) Determine the Thermal Energy of These Atoms