Assume molecules have an average diameter of 3.00 * 10-10 m. How many times larger is the mean free path than the diameter at one atmosphere and 0$\gamma$C?

Question

Quizplus · Accepted Answer

The mean free path is given by l = kT/(sqrt(2)*pi*d^2*p), where k is the Boltzmann constant, T is the temperature, d is the diameter, and p is the pressure. At one atmosphere and 0°C, T = 273 K and p = 1.01325*10^5 Pa. Plugging in these values and the given diameter, we get l = 6.6*10^-8 m. Thus, the mean free path is approximately 22 times larger than the diameter, which is closest to choice B (300).

Assume Molecules Have an Average Diameter of 3 γ\gammaγ C? A)500 B)300 C)700 D)1000 E)2500

Assume Molecules Have an Average Diameter of 3 $\gamma$ C?
A)500
B)300
C)700
D)1000
E)2500