Factor.
-$$\mathrm { t } ( 2 - \mathrm { m } ) + \mathrm { s } ( 2 - \mathrm { m } )$$
A) No common factor
B) $( t - s ) ( 2 - m )$
C) $\mathrm { t } ( 2 - \mathrm { m } ) + \mathrm { s }$
D) $( t + s ) ( 2 - m )$

Question

Quizplus · Accepted Answer

The expression can be factored by taking out the common factor $(2 - m)$ from both terms, resulting in $(t + s)(2 - m)$.

Factor - t(2−m)+s(2−m)\mathrm { t } ( 2 - \mathrm { m } ) + \mathrm { s } ( 2 - \mathrm { m } )t(2−m)+s(2−m)

Factor
- $\mathrm { t } ( 2 - \mathrm { m } ) + \mathrm { s } ( 2 - \mathrm { m } )$