Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. The cheerleaders for a local professional basketball team must be between 65.5 and 68.0
Inches. If a woman is randomly selected, what is the probability that her height is between 65.5 and 68.0
Inches?
A)0.1844
B)0.9608
C)0.7881
D)0.3112

Question

Quizplus · Accepted Answer

The probability that a woman's height is between 65.5 and 68.0 inches is the area under the normal distribution curve between those two values. Using a standard normal distribution table, we find that the area between z = (65.5 - 63.6) / 2.5 = 0.76 and z = (68.0 - 63.6) / 2.5 = 1.76 is 0.1844.

Assume That the Heights of Women Are Normally Distributed with a Mean