Solve the problem.
-A parallelogram has areaas area $\frac { x ^ { 2 } + 9 x + 8 } { x } \text { and height } \frac { x ^ { 5 } } { x + 1 }$ . Find the length of its base, by dividing its area by its height.
A) $\frac { x + 8 } { x ^ { 4 } }$
B) $x ^ { 4 } ( x + 8 )$
C) $\frac { ( x + 8 ) ( x + 1 ) ^ { 2 } } { x ^ { 4 } }$
D) $\frac { ( x + 8 ) ( x + 1 ) ^ { 2 } } { x ^ { 6 } }$

Question

Solve the problem.
-A parallelogram has areaas area $\frac { x ^ { 2 } + 9 x + 8 } { x } \text { and height } \frac { x ^ { 5 } } { x + 1 }$ . Find the length of its base, by dividing its area by its height. 
A) $\frac { x + 8 } { x ^ { 4 } }$ 
B) $x ^ { 4 } ( x + 8 )$ 
C) $\frac { ( x + 8 ) ( x + 1 ) ^ { 2 } } { x ^ { 4 } }$ 
D) $\frac { ( x + 8 ) ( x + 1 ) ^ { 2 } } { x ^ { 6 } }$

Quizplus · Accepted Answer

The Answer of Solve the problem.
-A parallelogram has areaas area $\frac { x ^ { 2 } + 9 x + 8 } { x } \text { and height } \frac { x ^ { 5 } } { x + 1 }$ . Find the length of its base, by dividing its area by its height. 
A) $\frac { x + 8 } { x ^ { 4 } }$ 
B) $x ^ { 4 } ( x + 8 )$ 
C) $\frac { ( x + 8 ) ( x + 1 ) ^ { 2 } } { x ^ { 4 } }$ 
D) $\frac { ( x + 8 ) ( x + 1 ) ^ { 2 } } { x ^ { 6 } }$

Solve the Problem x2+9x+8x and height x5x+1\frac { x ^ { 2 } + 9 x + 8 } { x } \text { and height } \frac { x ^ { 5 } } { x + 1 }xx2+9x+8​ and height x+1x5​

Solve the Problem $\frac { x ^ { 2 } + 9 x + 8 } { x } \text { and height } \frac { x ^ { 5 } } { x + 1 }$