In the pseudocode for the dfs function for partitioning the vertices in a graph into disjointed components, what is the missing pseudocode statement? dfs(graph, v, s) :
Mark v as visited
S.add(v)
For each vertex, w, adjacent to v:
If w is unvisited:
<missing pseudocode>

Question

In the pseudocode for the dfs function for partitioning the vertices in a graph into disjointed components, what is the missing pseudocode statement? dfs(graph, v, s):
Mark v as visited
S.add(v)
For each vertex, w, adjacent to v:
If w is unvisited:
<missing pseudocode>
A) s.add(w)
B) dfs(graph, v, s)
C) s.add(v)
D) dfs(graph, w, s)

Quizplus · Accepted Answer

The missing pseudocode statement should call the dfs function recursively with w as the new starting vertex, since we need to explore all connected components in the graph. Therefore, we choose option D as the correct answer. Options A and C would add the vertex to the same set s as v, which would not explore all connected components. Option B would not explore all possible neighbors of v before moving on to other vertices.

In the Pseudocode for the Dfs Function for Partitioning the Vertices