For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature: ( T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters, T in kelvins)
Assume an object is emitting blackbody radiation.
If the Kelvin temperature of a body is doubled, the wavelength of the most intense light is double the wavelength originally of the most intense light.

Question

For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature:  ( T in kelvins) 
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters, T in kelvins) 
Assume an object is emitting blackbody radiation. 
If the Kelvin temperature of a body is doubled, the wavelength of the most intense light is double the wavelength originally of the most intense light.

Quizplus · Accepted Answer

According to the second law mentioned, the wavelength of the most intense light is inversely proportional to the body's absolute temperature. So if the Kelvin temperature of a body is doubled, the wavelength of the most intense light would be halved (not doubled).

For a Body Emitting Blackbody Radiation, the Total Power Emitted