For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature: ( T in kelvins)
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters, T in kelvins)
Assume an object is emitting blackbody radiation.
A body in a room at 300 K is heated to 3,000 K. The amount of energy radiated each second by the body increases 10,000 times.

Question

For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature:  ( T in kelvins) 
and the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters, T in kelvins) 
Assume an object is emitting blackbody radiation. 
A body in a room at 300 K is heated to 3,000 K. The amount of energy radiated each second by the body increases 10,000 times.

Quizplus · Accepted Answer

The power emitted by a body emitting blackbody radiation is proportional to the 4th power of its temperature. Therefore, increasing the temperature from 300 K to 3,000 K will increase the amount of energy radiated each second by a factor of (3,000/300)^4 = 10,000. This means that A) is true.

For a Body Emitting Blackbody Radiation, the Total Power Emitted