How many atoms are present in 2.7 g of B?

Name: How many atoms are present in 2.7 g of B?
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Question

Quizplus · Accepted Answer

The correct answer is A because 2.7 g of B contains 1.5×10^23 atoms. This is because the atomic mass of B is 10.811 g/mol, so 2.7 g of B is equal to 2.7 g / 10.811 g/mol = 0.25 mol of B. 1 mol of B contains 6.022×10^23 atoms, so 0.25 mol of B contains 0.25 mol × 6.022×10^23 atoms/mol = 1.5×10^23 atoms.

How Many Atoms Are Present in 2