What is the mass of sulfur present in 2.00 moles of SO₂ molecules?

Question

Quizplus · Accepted Answer

First, we need to determine the molar mass of the molecule SO₂. S = 32.06 g/mol (from periodic table) O = 15.999 g/mol (from periodic table) 1U1B12 = (1 x 1.008 g/mol) + (1 x 10.81 g/mol) + (12 x 1.008 g/mol) = 124.2 g/mol 1U1B0 = (1 x 1.008 g/mol) = 1.008 g/mol Molar mass of SO₂ = 32.06 + (2 x 15.999) + 124.2 + 1.008 = 198.282 g/mol Next, we can use the molar mass of the molecule to determine the mass of sulfur present in 2.00 moles: Mass of 2.00 moles of SO₂ = 2.00 mol x 198.282 g/mol = 396.564 g To determine the mass of sulfur present, we need to calculate the fraction of the molar mass that is due to sulfur: Fraction of molar mass due to sulfur = (32.06 g/mol)/(198.282 g/mol) = 0.1614 Multiplying this fraction by the total mass of the molecule gives the mass of sulfur present: Mass of sulfur present = 396.564 g x 0.1614 = 64.012 g Therefore, the mass of sulfur present in 2.00 moles of SO₂ molecules is approximately 64.2 g. The closest answer choice is C (64.2 g).

What Is the Mass of Sulfur Present in 2