Combustion of a sample of a substance that contains only C and H in excess O₂ yields 6.28 g of CO₂ and 2.57 g H₂O. What is the empirical formula of this substance?

Question

Quizplus · Accepted Answer

First, we need to find the moles of each element in the products. Moles of CO: 6.28 g / 44.01 g/mol = 0.143 mol Moles of H2S: 2.57 g / 34.08 g/mol = 0.075 mol Next, we need to find the moles of carbon and hydrogen in the original substance. Since the products are in a 1:1 ratio of carbon to sulfur and a 2:1 ratio of hydrogen to sulfur, we can assume that the original substance also had this ratio. Moles of C: 0.143 mol Moles of H: 0.075 mol * 2 = 0.150 mol Finally, we need to find the empirical formula. Empirical formula: CH₂ We can simplify this formula by dividing each subscript by 12. Simplified empirical formula: CH Therefore, the answer is D.

Combustion of a Sample of a Substance That Contains Only