What is the molecular formula of a compound with an empirical formula of C₃H₆O and a molar mass of 174 g/mol?

Question

Quizplus · Accepted Answer

1. Calculate the empirical formula's molar mass: C: 1 x 12.01 g/mol = 12.01 g/mol S: 2 x 32.07 g/mol = 64.14 g/mol B: 13 x 10.81 g/mol = 140.53 g/mol H: 1 x 1.01 g/mol = 1.01 g/mol O: 1 x 15.99 g/mol = 15.99 g/mol Empirical formula molar mass = 233.68 g/mol 2. Calculate the ratio between the empirical formula molar mass and the molar mass given in the question: 174 g/mol ÷ 233.68 g/mol = 0.744 3. Multiply all the subscripts by 0.744 and round to the nearest whole number: C: 1 x 0.744 = 0.744 ≈ 1 S: 2 x 0.744 = 1.488 ≈ 1 B: 13 x 0.744 = 9.672 ≈ 10 H: 1 x 0.744 = 0.744 ≈ 1 O: 1 x 0.744 = 0.744 ≈ 1 Molecular formula: C₀HO Simplify to: CSUB10HSUB1O

What Is the Molecular Formula of a Compound with an Empirical