What mass of Al₂S₃ is formed when 5.00 g of Al is heated with 10.0 g of S?
There are no other products.

Question

What mass of Al₂S₃ is formed when 5.00 g of Al is heated with 10.0 g of S? There are no other products.

Quizplus · Accepted Answer

The balanced chemical equation is 2Al + 3S → Al2S3. The molar mass of Al is 26.98 g/mol and S is 32.07 g/mol. Calculate moles of Al (5.00 g / 26.98 g/mol = 0.185 mol) and S (10.0 g / 32.07 g/mol = 0.312 mol). The stoichiometry requires 2 moles of Al for every 3 moles of S. Al is the limiting reactant (0.185 mol Al requires 0.277 mol S, but only 0.312 mol S is available). The moles of Al2S3 formed is 0.185 mol Al / 2 = 0.0925 mol. The molar mass of Al2S3 is 150.16 g/mol, so the mass is 0.0925 mol × 150.16 g/mol = 13.9 g.

What Mass of Al2S3 Is Formed When 5

What Mass of Al₂S₃ Is Formed When 5