How many grams of PCl₅ can be produced from the reaction of 14 g of P with 34 g of Cl₂?
The equation is:
2 P + 5 Cl₂→2 PCl₅

Question

How many grams of PCl₅ can be produced from the reaction of 14 g of P with 34 g of Cl₂? The equation is: 2 P + 5 Cl₂→2 PCl₅

Quizplus · Accepted Answer

The balanced equation is:2 P + 5 Cl₂→2 PCl₅Moles of P = 14 g / 31 g/mol = 0.45 molMoles of Cl₂ = 34 g / 71 g/mol = 0.48 molThe mole ratio of P to Cl₂ is 2:5, so Cl₂ is in excess.Moles of PCl₅ produced = 0.45 mol * (2 mol PCl₅ / 2 mol P) = 0.45 molMass of PCl₅ produced = 0.45 mol * 208.28 g/mol = 94 g

How Many Grams of PCl5 Can Be Produced from the Reaction

How Many Grams of PCl₅ Can Be Produced from the Reaction