Exhibit 3-3 0.75 moles of aluminum metal (Al) and 0.50 moles of chlorine gas (Cl₂) are allowed to react as shown in the reaction below:
2 Al (s) + 3 Cl₂ (g) →2 AlCl₃ (s)
Refer to Exhibit 3-3. Which substance is the limiting reactant in this reaction?

Question

Quizplus · Accepted Answer

The balanced equation shows that 2 moles of Al react with 3 moles of Cl₂. Therefore, 0.75 moles of Al would require 1.125 moles of Cl₂ to fully react. Since only 0.50 moles of Cl₂ are available, Cl₂ is the limiting reactant.