What is the bond order for NO⁺?

Question

Quizplus · Accepted Answer

To determine bond order, we need to find the number of bonding electrons and the number of antibonding electrons, and then subtract the latter from the former before dividing by 2. For NO⁺, we can first write out the molecular orbital diagram and fill in the electrons: N: σ2s(2) σ*2s(0) σ2p(2) σ*2p(0) π2p(4) π*2p(0) O: σ2s(2) σ*2s(0) σ2p(2) σ*2p(0) π2p(2) π*2p(1) ^{: σ2s(2) σ*2s(0) σ2p(2) π2p(2) σ2p(1) π*2p(0)}: σ2s(2) σ*2s(0) σ2p(2) π2p(2) σ2p(2) π*2p(0) Counting the number of bonding and antibonding electrons, we get: Bonding: 2(N-N) + 2(^-) + 2(^{-N) + 2(O-N) + 2(O-}) = 4+4+4+4+2 = 18 Antibonding: 2(N-^{) + 2(N-O) + 2(}-O) = 2+4+1 = 7 Subtracting the number of antibonding electrons from the number of bonding electrons and dividing by 2, we get: (18-7)/2 = 11/2 which is approximately 3. Therefore, the bond order is 3, and the answer is C.

What Is the Bond Order for NO+

What Is the Bond Order for NO⁺