What is the bond order for CN^-?

Question

Quizplus · Accepted Answer

To determine bond order, we need to calculate the number of bonding electrons minus the number of antibonding electrons, and then divide by two. For CN^-, we can draw the Lewis structure as follows: C:N:S::U:P: S :: S There are a total of 14 valence electrons in this molecule. Drawing the Lewis structure, we see that there are 5 bonding pairs of electrons and 1 antibonding pair of electrons. Therefore, the bond order is (5-1)/2 = 2.

What Is the Bond Order for CN -

What Is the Bond Order for CN^-