How many grams of solute are present in 164.1 mL of 0.207 M calcium acetate, Ca(C2H3O2) 2?
MM[Ca(C2H3O2) 2] = 158.17 g/mol
A) 0.200 g Ca(C2H3O2) 2
B) 0.215 g Ca(C2H3O2) 2
C) 4.66 g Ca(C2H3O2) 2
D) 5.01 g Ca(C2H3O2) 2
E) 5.37 g Ca(C2H3O2) 2
Correct Answer:
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