How many grams of KBr are required to prepare 1.50 L of 0.257 M aqueous solution?
MM(KBr) = 119.00 g/mol

Question

Quizplus · Accepted Answer

First, we need to use the formula:

Molarity (M) = moles of solute (n) / volume of solution in liters (V)

Rearranging the equation:

n = M x V

Substituting the given values:

n = 0.257 mol/L x 1.50 L = 0.3865 mol KBr

To convert moles to grams, we use the formula:

mass = moles x molar mass

Substituting the given values:

mass = 0.3865 mol x 119.00 g/mol = 45.9 g KBr

Therefore, the answer is C. 45.9 g KBr is required to prepare 1.50 L of 0.257 M aqueous solution.

How Many Grams of KBr Are Required to Prepare 1