What is the mole fraction of glucose in a solution prepared by dissolving 9.01 grams of glucose, C₆H₁₂O₆, in 17.1 grams of water?
Molar Mass(C₆H₁₂O₆) = 180.16 g/mol and Molar Mass(H₂O) = 18.02 g/mol

Question

Quizplus · Accepted Answer

The mole fraction of glucose is calculated by dividing the moles of glucose by the total moles of the solution. Moles of glucose = 9.01 g / 180.16 g/mol = 0.050 moles. Moles of water = 17.1 g / 18.02 g/mol = 0.949 moles. Total moles = 0.050 + 0.949 = 0.999 moles. Mole fraction of glucose = 0.050 / 0.999 = 0.0503.

What Is the Mole Fraction of Glucose in a Solution