A solution is prepared by mixing 22 g ethylene glycol [C₂H₄(OH)₂, molar mass = 62 g/mol] with 108 g of water. What is the mole fraction of ethylene glycol in the solution?

Question

Quizplus · Accepted Answer

The moles of ethylene glycol are 22 g / 62 g/mol = 0.355 moles. The moles of water are 108 g / 18 g/mol = 6 moles. The mole fraction of ethylene glycol is 0.355 / (0.355 + 6) = 0.056.

A Solution Is Prepared by Mixing 22 G Ethylene Glycol