How many grams of Na₂CO₃ are required to prepare 25.0 mL of a 2.00% (m/v) Na₂CO₃ solution?

Question

Quizplus · Accepted Answer

First, we need to convert the given percentage concentration to a mass concentration in g/mL: 2.00% (m/v) = 2.00 g/100 mL = 0.0200 g/mL Next, we can use the formula: C = (m/v) where C is the concentration in g/mL, m is the mass of solute in g, and v is the volume of solution in mL. Rearranging this formula, we get: m = C x v Plugging in the values we know: m = 0.0200 g/mL x 25.0 mL = 0.500 g Therefore, we need 0.500 g of Na₂CO₃ to prepare 25.0 mL of a 2.00% (m/v) solution. Choice (B) is the correct answer.

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How Many Grams of Na₂CO₃ Are Required to Prepare 25