A 2.90 m aqueous solution of acetic acid, C₂H₄O₂ (60.0 g/mol), has a density of 1.020 g/mL. Calculate the molarity of the solution.

Question

Quizplus · Accepted Answer

To find molarity, use the formula: Molarity = moles of solute / liters of solution. First, calculate the mass of the solution using its density: 1.020 g/mL * 1000 mL = 1020 g. Then, find the mass of water: 1020 g - (2.90 mol * 60.0 g/mol) = 846 g. Convert this to kg: 0.846 kg. Since molality is moles of solute per kg of solvent, 2.90 mol/kg * 0.846 kg = 2.45 mol. Finally, convert the mass of the solution to liters: 1020 g / 1.020 g/mL = 1 L. Molarity = 2.45 mol / 1 L = 2.52 M.

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