A 1.14 molar solution of ammonium chloride (molar mass = 53.50 g/mol) has a density of 1.019 g/mL. What is the molality of the solution?

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Quizplus · Accepted Answer

To find molality, we need the mass of the solvent. First, calculate the mass of the solution: 1.14 mol * 53.50 g/mol = 61.09 g of NH4Cl. The volume of the solution is 1 L (1000 mL), so the mass of the solution is 1000 mL * 1.019 g/mL = 1019 g. The mass of the solvent (water) is 1019 g - 61.09 g = 957.91 g = 0.95791 kg. Molality = moles of solute / kg of solvent = 1.14 mol / 0.95791 kg = 1.19 m.

A 114 Molar Solution of Ammonium Chloride (Molar Mass = 53