The solubility of Helium gas at 25 ° C and 2.0 atm of pressure is 8.4×10^{- 4} M. After determining Henry's Law constant for Helium, what is the solubility of Helium gas at 6.5 atm of pressure?

Question

Quizplus · Accepted Answer

Henry's Law states that the solubility of a gas is directly proportional to its pressure. The constant (k) can be calculated using the initial conditions: k = 8.4×10^-4 M / 2.0 atm = 4.2×10^-4 M/atm. At 6.5 atm, solubility = k × 6.5 atm = 4.2×10^-4 M/atm × 6.5 atm = 2.7×10^-3 M.

The Solubility of Helium Gas at 25 ° C and 2.0