What is the boiling point for a 0.35 m solution of glycerol (C₃H₈O₃) in ethanol?
Boiling point(ethanol) = 78.4 ° C; K_b(ethanol) = 1.22 ° C/ m .

Question

What is the boiling point for a 0.35 m solution of glycerol (C₃H₈O₃) in ethanol? Boiling point(ethanol) = 78.4 ° C; K_b(ethanol) = 1.22 ° C/ m .

Quizplus · Accepted Answer

To calculate the boiling point of the solution, we use the equation:
ΔTb = kb x m
where ΔTb is the change in boiling point, kb is the boiling point elevation constant, and m is the molality of the solution.

We are given the following values:
- ΔTb = boiling point of solution - boiling point of pure ethanol = Tb - 78.4°C
- kb = 1.22°C/m
- m = 0.35 mol/kg

Substituting these values into the equation, we get:
Tb - 78.4°C = 1.22°C/m x 0.35 mol/kg
Tb - 78.4°C = 0.427°C
Tb = 78.8°C

Therefore, the boiling point of the 0.35 m solution of glycerol in ethanol is 78.8°C, which is option D.

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