What is the freezing point of a 2.50 m solution of acetophenone dissolved in Lauric acid?
K_f(Lauric acid) = 2.72 ° C/ m ; T_{f, lauric acid} = 44.0 ° C

Question

What is the freezing point of a 2.50 m solution of acetophenone dissolved in Lauric acid? K_f(Lauric acid) = 2.72 ° C/ m ; T_{f, lauric acid} = 44.0 ° C

Quizplus · Accepted Answer

The freezing point depression can be calculated using the formula ΔT_f = i * K_f * m. Here, i = 1 for non-electrolytes, K_f = 2.72 °C/m, and m = 2.50 m. ΔT_f = 1 * 2.72 * 2.50 = 6.8 °C. The new freezing point is 44.0 °C - 6.8 °C = 37.2 °C.

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