Water has a k_f of 1.86 ° C/m and a freezing point of 0 ° C. What is the freezing point of a 0.10 m solution of a nonelectrolyte?

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Quizplus · Accepted Answer

The freezing point depression is calculated using the formula ΔTf = i * Kf * m, where ΔTf is the change in freezing point, i is the van't Hoff factor (which is 1 for a nonelectrolyte), Kf is the cryoscopic constant of water (1.86 °C/m), and m is the molality of the solution (0.10 m). Thus, ΔTf = 1 * 1.86 °C/m * 0.10 m = 0.186 °C. Since this is a depression, the freezing point is lowered by 0.186 °C from 0 °C, resulting in a new freezing point of -0.186 °C.

Water Has a Kf of 1

Water Has a K_f of 1