Consider the following second order reaction with a rate constant k = 10 M^{- 1}sec^{- 1} at 383 K:
NO₂ (g) →NO (g) + ¹/₂ O₂ (g)
If the initial concentration of NO₂ equals 1.5 M, what is the half-life for this reaction?

Question

Quizplus · Accepted Answer

For a second-order reaction, the half-life is given by t₁/₂ = 1 / (k[A]₀). Substituting the given values, t₁/₂ = 1 / (10 M⁻¹s⁻¹ × 1.5 M) = 6.7×10⁻² sec.

Consider the Following Second Order Reaction with a Rate Constant