The equilibrium constant for the reaction below is 2.5*10⁹ at 25 C.
2 HCl (g) H₂ (g) + Cl₂ (g) K eq (25 C) = 3.2*10^{- 34}
What can be stated about the relative equilibrium distribution for this mixture?

Question

The equilibrium constant for the reaction below is 2.5*10⁹ at 25 C.
2 HCl (g)

The equilibrium constant for the reaction below is 2.5*10<sup>9</sup> at 25 C. 2 HCl (g) H₂ (g) + Cl₂ (g) K eq (25 C) = 3.2*10<sup>- 34 </sup> What can be stated about the relative equilibrium distribution for this mixture? A) The mixture contains predominantly H<sub>2</sub>. B) The mixture contains predominantly Cl<sub>2</sub>. C) The mixture contains predominantly HCl. D) The mixture contains predominantly H<sub>2</sub> and Cl<sub>2</sub>. E) The mixture contains relatively equal amounts of H<sub>2</sub>, Cl<sub>2</sub> and HCl.

H₂ (g) + Cl₂ (g) K eq (25 C) = 3.2*10^{- 34}
What can be stated about the relative equilibrium distribution for this mixture?

Quizplus · Accepted Answer

The Answer of The equilibrium constant for the reaction below is 2.5*10⁹ at 25 C. 2 HCl (g) H₂ (g) + Cl₂ (g) K eq (25 C) = 3.2*10^{- 34} What can be stated about the relative equilibrium distribution for this mixture?

The Equilibrium Constant for the Reaction Below Is 2