Consider the reaction:
2 HI (g)
H₂ (g) + I2 (g)
Given K c = 1.26 10 - 3 at 25 C and equilibrium concentrations, H₂ eq = 0.0350 M and I2 eq = 0.0450 M, what is the equilibrium concentration of HI?
A) [HI]eq = 0.800 M
B) [HI]eq = 0.894 M
C) [HI]eq = 1.12 M
D) [HI]eq = 1.25 M
E) [HI]eq = 1.56 M
Correct Answer:
Verified
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