Exhibit 14-3 Consider the Reaction Below and Its Corresponding Equilibrium

Exhibit 14-3 Consider the reaction below and its corresponding equilibrium constant at 2000 C to answer the following question(s) :
N₂(g) + O₂(g) 2 NO (g) K c = 4.10*10^{- 4} (at 2000 C) Complete the table shown below for an experiment where 0.55 moles of N₂is mixed with 0.45 moles of O₂in a 1.00 Liter reaction vessel and the reaction mixture is allowed to come to equilibrium. Concentration N₂O₂ 2 NO Initial 0.55 M 0.45 M Change At equilibrium
-Refer to Exhibit 14-3. What equilibrium expression shown below would allow you to solve for x and therefore enable you to solve for the equilibrium concentrations of each of the substances present at equilibrium?

A) x²/(0.55 - x) (0.45 - x) = 4.1×10 ^{- 4}
B) 2x²/(0.55 + x) (0.45 + x) = 4.1×10 ^{- 4}
C) 2x²/(0.55 - x) (0.45 - x) = 4.1×10 ^{- 4}
D) 4x²/(0.55 - x) (0.45 - x) = 4.1×10 ^{- 4}
E) 2x²/(0.55 + x) (0.450 + x) = 4.1×10 ^{- 4}