Exhibit 14-5 Consider the Decomposition Reaction of Hydrogen Sulfide, H₂

Exhibit 14-5 Consider the decomposition reaction of Hydrogen sulfide, H₂ S, and the corresponding equilibrium constant as shown below to answer the following question(s) :
2 H₂ S (g) 2 H₂ (g) + S₂(g) K c = 9.30*10^{- 8}
Complete the following ICE table for when 0.150 moles of H₂ S is placed in a 1.00 liter container. Molar Conc, M H₂ S H₂ S₂Initial Change At equilibrium
-Refer to Exhibit 14-5. What equilibrium expression shown below would allow you to solve for x and therefore enable you to solve for the equilibrium concentrations of each of the substances present at equilibrium?

A) x³/(0.15 - x) ² = 9.30×10 ^{- 8}
B) 4x³/(0.15 - 2x) ² = 9.30×10 ^{- 8}
C) 2x³/(0.15 - 2x) ² = 9.30×10 ^{- 8}
D) 4x³/(0.15 - x) ² = 9.30×10 ^{- 8}
E) 2x³/(0.15 + 2x) ² = 9.30×10 ^{- 8}