The solubility of CaF₂ in water is 2.7×10^{- 2} g/liter. What is the K _sp for this compound?

Question

Quizplus · Accepted Answer

The Ksp expression for CaF₂ is: CaF₂ → Ca2+ + F- + S2O32- Ksp = [Ca2+][F-][S2O32-] Since the compound dissociates into one Ca2+ ion, one F- ion, and one S2O32- ion, the solubility of CaF₂ can be used to determine the concentration of each ion at equilibrium. 2.7×10^{- 2} g/L = [Ca2+] + [F-] + [S2O32-] Assuming complete dissociation, [Ca2+] = [F-] = [S2O32-] = x 2.7×10^{- 2} g/L = 3x x = 9×10^{- 3} Substituting x back into the Ksp expression, Ksp = (9×10^{- 3})3 = 1.7×10^{- 10} Therefore, the correct answer is D.

The Solubility of CaF2 in Water Is 2

The Solubility of CaF₂ in Water Is 2