At 25 ° C, K _p = 4.34×10^{- 5} for PH₃ (g) + HI (g) →PH₄I (s) . What is D G ° for this reaction?
(R = 8.314 J/mol × K)

Name: At 25 ° C, K p = 4.34×10 - 5 for PH 3 (g) + HI (g)→PH 4 I (s). What is D G ° for this reaction? (R = 8.314 J/mol × K)
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Question

At 25 ° C, K _p = 4.34×10^{- 5} for PH₃ (g) + HI (g)→PH₄I (s). What is D G ° for this reaction? (R = 8.314 J/mol × K)

Quizplus · Accepted Answer

The standard Gibbs free energy change (ΔG°) can be calculated using the equation ΔG° = -RTlnK. Substituting the given values (R = 8.314 J/mol·K, T = 298 K, Kp = 4.34×10^-5), we find ΔG° = 24.9 kJ.