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Use CO = - 137 KJ/mol, Cl₂ =

Question 101

Multiple Choice

Use Use CO = - 137 kJ/mol, Cl₂ = 0. kJ/mol, COCl₂ = - 205 kJ/mol, and R = 8.314 J/mol K to calculate the free energy change at 298 K for: CO (g, 0.2 atm) + Cl₂ (g, 0.4 atm) COCl₂ (g, 10 atm) A) - 12030 kJ B) - 80 kJ C) - 68 kJ D) - 56 kJ E) +11894 kJ CO = - 137 kJ/mol, Use CO = - 137 kJ/mol, Cl₂ = 0. kJ/mol, COCl₂ = - 205 kJ/mol, and R = 8.314 J/mol K to calculate the free energy change at 298 K for: CO (g, 0.2 atm) + Cl₂ (g, 0.4 atm) COCl₂ (g, 10 atm) A) - 12030 kJ B) - 80 kJ C) - 68 kJ D) - 56 kJ E) +11894 kJ Cl₂ = 0. kJ/mol, Use CO = - 137 kJ/mol, Cl₂ = 0. kJ/mol, COCl₂ = - 205 kJ/mol, and R = 8.314 J/mol K to calculate the free energy change at 298 K for: CO (g, 0.2 atm) + Cl₂ (g, 0.4 atm) COCl₂ (g, 10 atm) A) - 12030 kJ B) - 80 kJ C) - 68 kJ D) - 56 kJ E) +11894 kJ COCl₂ = - 205 kJ/mol, and R = 8.314 J/mol K to calculate the free energy change at 298 K for:
CO (g, 0.2 atm) + Cl₂ (g, 0.4 atm) Use CO = - 137 kJ/mol, Cl₂ = 0. kJ/mol, COCl₂ = - 205 kJ/mol, and R = 8.314 J/mol K to calculate the free energy change at 298 K for: CO (g, 0.2 atm) + Cl₂ (g, 0.4 atm) COCl₂ (g, 10 atm) A) - 12030 kJ B) - 80 kJ C) - 68 kJ D) - 56 kJ E) +11894 kJ COCl₂ (g, 10 atm)


A) - 12030 kJ
B) - 80 kJ
C) - 68 kJ
D) - 56 kJ
E) +11894 kJ

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