What is the value of the equilibrium constant, K , at 298 K for the following reaction?
Sn (s) + Pb 2+ (aq) 
Sn 2+ (aq) + Pb (s) E cell = 0.01 V
A) K = 5×10 - 1
B) K = 7×10 - 1
C) K = 8×10 - 1
D) K = 1
E) K = 2
Correct Answer:
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