A current of 0.452 amperes was passed through molten MgCl₂ for 50,000 seconds. If the reaction is MgCl₂→Mg (s) + Cl₂ (g), calculate the number of grams of Mg metal produced. (1 F = 96500 C/mol e^-)

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The amount of Mg produced can be calculated using Faraday's laws of electrolysis. First, calculate the total charge passed through the molten MgCl2: Q = current × time = 0.452 A × 50,000 s = 22,600 C. The molar mass of Mg is approximately 24.305 g/mol, and it requires 2 moles of electrons (2 F) to reduce one mole of Mg2+ to Mg. Therefore, the mass of Mg produced is given by: mass = (Q / (2 × 96500 C/mol)) × 24.305 g/mol = (22600 / 193000) × 24.305 ≈ 2.85 g.

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