The nuclide 226 Ra undergoes a series of alpha and beta decays, finally producing stable 206 Pb. 
+ A 
+ B 
Give the values of A and B in the equation.
A) A = 5, B = 4
B) A = 4, B = 6
C) A = 6, B = 8
D) A = 8, B = 6
E) A = 4, B = 5
Correct Answer:
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