Use the discriminant to determine whether the equation has two nonreal complex solutions, one real solution with a multiplicity of two, or two real solutions. y 2 $-$ 6 y $-$ 27 = 0
A) two real solutions
B) one real solution with a multiplicity of two
C) two nonreal complex solutions

Question

Quizplus · Accepted Answer

The discriminant of a quadratic equation $ax^2 + bx + c = 0$ is given by $b^2 - 4ac$. For the equation $y^2 - 6y - 27 = 0$, $a = 1$, $b = -6$, and $c = -27$. Thus, the discriminant is $(-6)^2 - 4(1)(-27) = 36 + 108 = 144$. Since the discriminant is positive, the equation has two real solutions.

Use the Discriminant to Determine Whether the Equation Has Two −-−

Use the Discriminant to Determine Whether the Equation Has Two $-$