Use the quadratic formula to solve the quadratic equation. 256 x ² + 96 x + 9 = 0 A) $\left\{ - \frac { 3 } { 16 } \right\}$ B) $\left\{ - \frac { 5 } { 16 } \right\}$ C) $\left\{ \frac { 3 } { 16 } \right\}$ D) $\left\{ - \frac { 16 } { 3 } \right\}$ E) $\left\{ \frac { 16 } { 3 } \right\}$

Question

Quizplus · Accepted Answer

The quadratic equation is $256x^2 + 96x + 9 = 0$. Using the quadratic formula $x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$ with $a = 256$, $b = 96$, and $c = 9$, we find that the discriminant $b^2-4ac = 96^2 - 4*256*9$ is a perfect square, leading to a single real solution $x = -\frac{3}{16}$, since the equation simplifies to a perfect square trinomial.

Use the Quadratic Formula to Solve the Quadratic Equation {−316}\left\{ - \frac { 3 } { 16 } \right\}{−163​}

Use the Quadratic Formula to Solve the Quadratic Equation $\left\{ - \frac { 3 } { 16 } \right\}$