Solve the Equation $$3 = 4 + \sqrt { 4 x + 67 }$$

Solve the equation. Write all apparent solutions. Which of them are extraneous? $$3 = 4 + \sqrt { 4 x + 67 }$$

A) $- \frac { 33 } { 2 }$ is extraneous solution, no solution
B) $- \frac { 35 } { 2 }$ is extraneous solution, $- \frac { 33 } { 2 }$
C) $- \frac { 35 } { 2 }$ is extraneous solution, no solution
D) $- \frac { 33 } { 2 }$
E) $- \frac { 35 } { 2 }$