The Orbital Speed ( S )Of an Earth Satellite Is $\sqrt { r } = \frac { 2.029 \times 10 ^ { 7 } } { s }$

The orbital speed ( s ) of an earth satellite is related to its distance ( r ) from the earth's center by the formula $\sqrt { r } = \frac { 2.029 \times 10 ^ { 7 } } { s }$ . If the satellite's orbital speed is $6 \times 10 ^ { 3 }$ meters per second, find its altitude a (in meters) above the earth's surface, as shown in the illustration. Round the answer to the nearest meter.

A) 2,244
B) 5,595
C) 5,035,169
D) 5,034,669
E) 5,035,669