Exhibit 11-2
The following question(s) pertain to the dissolution of 200.0 g of KMnO₄ into 600.0g. of water.
Refer to Exhibit 11-2. What is the mole fraction of MnO₄^- ions in the solution?

Question

Exhibit 11-2 The following question(s) pertain to the dissolution of 200.0 g of KMnO₄ into 600.0g. of water. Refer to Exhibit 11-2. What is the mole fraction of MnO₄^- ions in the solution?

Quizplus · Accepted Answer

To find the mole fraction of MnO4- ions, first calculate the moles of KMnO4 (molar mass = 158.04 g/mol) and water (molar mass = 18.02 g/mol). Moles of KMnO4 = 200.0 g / 158.04 g/mol = 1.265 moles. Moles of water = 600.0 g / 18.02 g/mol = 33.3 moles. The mole fraction of MnO4- is the moles of KMnO4 divided by the total moles (KMnO4 + water), which is 1.265 / (1.265 + 33.3) = 0.0353.

Exhibit 11-2 The Following Question(s) Pertain to the Dissolution of 200.0 G