Nitrogen gas reacts with hydrogen gas to produce ammonia.
3 H₂(g) + N₂(g) → 2 NH₃(g)
How many grams of nitrogen are required to produce 1.000 g of ammonia?

Question

Nitrogen gas reacts with hydrogen gas to produce ammonia. 3 H₂(g) + N₂(g) → 2 NH₃(g) How many grams of nitrogen are required to produce 1.000 g of ammonia?

Quizplus · Accepted Answer

The balanced chemical equation shows that 1 mole of nitrogen gas (N2) reacts with 3 moles of hydrogen gas (H2) to produce 2 moles of ammonia (NH3). The molar mass of nitrogen is 14.01 g/mol, and the molar mass of ammonia is 17.03 g/mol. Therefore, 1.000 g of ammonia contains 1.000 g / 17.03 g/mol = 0.0587 mol of ammonia. According to the balanced chemical equation, 0.0587 mol of ammonia requires 0.0587 mol / 2 = 0.0293 mol of nitrogen gas. The mass of nitrogen gas required is 0.0293 mol * 14.01 g/mol = 0.4112 g.

Nitrogen Gas Reacts with Hydrogen Gas to Produce Ammonia