After creating two variables as follows:
Char message1[81] = "this is a string";
Char *message2 = "this is a string";
The statement ____ is not valid in C.
A) message1 = "A new message";
B) message2 = "A new message";
C) message2 = message1;
D) message2[0] = 'T';

Question

Quizplus · Accepted Answer

Option A is not valid because `message1` is an array name, which in C, is a constant pointer. You cannot change the base address of an array after its declaration.

After Creating Two Variables as Follows